Answer:
The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by
= [tex]{\frac{(6.674\times 10^{-11}N. m^2/kg^2)(5.97\times 10^{24}kg) }{(10\times10^3)^2}[/tex] = 3984378 m / [tex]s^{2}[/tex]
Explanation:
The force of gravity on a 700 kg satellite if its 10 km above Earth's surface is given by
= [tex]{\frac{(6.674\times 10^{-11}N. m^2/kg^2)(5.97\times 10^{24}kg) }{(10\times10^3)^2}[/tex] = 3984378 m / [tex]s^{2}[/tex]
