Answer:
Average rate of change [tex]=\frac{1}{8}[/tex]
Step-by-step explanation:
Given interval are from [tex]x=0\ to\ x=5[/tex]
Also,[tex]=\frac{1}{2^3}x=\frac{1}{8}x[/tex]
Average rate of change[tex]=\frac{f(b)-f(a)}{b-a}\ for\ given\ interval\ [a,b][/tex]
Here given intervals are [tex]a=0\ and\ b=5[/tex]
Plugging these value in formula, we get.
Average rate of change[tex]=\frac{\frac{1}{8}(5)-\frac{1}{8}(0)}{5-0}\\\\=\frac{\frac{1}{8}(5)-0}{5-0}\\ \\=\frac{\frac{1}{8}(5)}{5}\\\\=\frac{1}{8}[/tex]
