Respuesta :

frika

Answer:

See explanation

Step-by-step explanation:

Given

[tex](8x+12y)^2+(6x+9y)^2=(10x+15y)^2[/tex]

Note

[tex](8x+12y)^2=(4(2x+3y))^2=16(2x+3y)^2\\ \\(6x+9y)^2=(3(2x+3y))^2=9(2x+3y)^2\\ \\(10x+15y)^2=(5(2x+3y))^2=25(2x+3y)^2[/tex]

Since

[tex]16(2x+3y)^2+9(2x+3y)^2=(2x+3y)^2(16+9)=25(2x+3y)^2,[/tex]

this is an identity

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