Answer:
2.88×10⁻⁹ s
2.40×10¹⁵ m/s²
Explanation:
Given:
v₀ = 12300 m/s
v = 6.92×10⁶ m/s
Δx = 0.997 cm = 0.00997 m
Part 1) Find: t
Δx = ½ (v + v₀)t
0.00997 m = ½ (6.92×10⁶ m/s + 12300 m/s) t
t = 2.88×10⁻⁹ s
Part 2) Find: a
(6.92×10⁶ m/s)² = (12300 m/s)² + 2a (0.00997 m)
a = 2.40×10¹⁵ m/s²
