Answer:
r = 4,
theta = pi/4
Step-by-step explanation:
A cartesian pair (x,y) will have the following polar coordinates:
[tex]r = \sqrt(x^2 + y^2)[\tex]
theta = arctan(y/x)
So for your pair:
[tex]r = \sqrt{(2\sqrt{2})^2 + (2\sqrt{2})^2} [\tex]
[tex]r = \sqrt{8+8} [\tex]
[tex]r = \sqrt{16} [\tex]
r = 4.
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theta = arctan(1)
What is the angle that has tan = 1? It is pi/4. So arctan(1) = pi/4 = theta
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