Answer:
[tex]\large\boxed{A.\ y-3=\dfrac{2}{3}(x-3)}[/tex]
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point on a line
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (3, 3) and (6, 5).
Substitute:
[tex]m=\dfrac{5-3}{6-3}=\dfrac{2}{3}[/tex]
Take the point (3, 3):
[tex]y-3=\dfrac{2}{3}(x-3)[/tex]
