Answer: the correct answer is f= 0.8747 oscillations/sec
Explanation:
The first bit of info allows you to find the spring constant; Β
K = force of compression/compression Β
where the force of compression is the "added" weight on the spring; Β
K = (83)(9.8)/(.016) Β Β Β Β Β Β Β K= 50837.5
Once you have ,K , you can use the frequency relation between ,K, and total mass on spring , Β Β Β M= 1600Kg + 83Kg Β M=1683 kg, as; Β
f =(1/2Pi)SqRt[K/M] oscillations/sec
f= (1/2 (3.1416)SqRt (50837.5/1683)
f=1/6.2832)SqRt 30.2065
f= Β 0.1592 *5.4960 Β Β Β Β Β Β f= 0.8747 oscillations/sec
