Answer:
{4, - 1}
Step-by-step explanation:
Given
2y² - 6y - 8 = 0 ← in standard form
with a = 2, b = - 6, c = - 8
Using the quadratic formula to solve for y
y = ( - (- 6) ± [tex]\sqrt{(-6)^2-(4(2)(-8)}[/tex] ) / (2 × 2)
= ( 6 ± [tex]\sqrt{36+64}[/tex] ) / 4
= ( 6 ± [tex]\sqrt{100}[/tex] ) / 4
= ( 6 ± 10 ) / 4
x = [tex]\frac{6+10}{4}[/tex] = [tex]\frac{16}{4}[/tex] = 4
OR
x = [tex]\frac{6-10}{4}[/tex] = [tex]\frac{-4}{4}[/tex] = - 1
Solution is { 4, - 1 }
