Respuesta :

Cxlver

Answer:

[tex]5\sqrt{2}[/tex]

Step-by-step explanation:

The formula for the length of a vector/line in your case.

[tex]L = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} = \sqrt{[4 - (-1)]^2 + [2 -(-3)]^2} = \sqrt{5^2 + 5^2} = \sqrt{50} = 5\sqrt{2}[/tex]

wolfiewolffromsketch

Answer: Mark them BRAINLIEST

Step-by-step explanation:

Because they helped my little sister out and they deserve it! :D

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