Answer:
[tex]A.\ y-6=-\dfrac{5}{6}(x+5)\\\\B.\ y-1=-\dfrac{5}{6}(x-1)[/tex]
Step-by-step explanation:
The point-slope form of an equation of a line:
[tex]y-y_1=m(x-x_1)[/tex]
m - slope
(x₁, y₁) - point
The formula of a slope:
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
We have the points (-5, 6) and (1, 1). Substitute:
[tex]m=\dfrac{1-6}{1-(-5)}=\dfrac{-5}{6}\\\\\text{For point (-5, 6):}\\\\y-6=-\dfrac{5}{6}(x-(-5))\\\\y-6=-\dfrac{5}{6}(x+5)[/tex]
[tex]\text{For point (1, 1):}\\\\y-1=-\dfrac{5}{6}(x-1)[/tex]
