chloeboo5210
chloeboo5210 chloeboo5210
  • 02-12-2018
  • Mathematics
contestada

find the equation of the straight line passing through the point (0,-1) which is perpendicular to the line y=-3/4x-3

Respuesta :

jimrgrant1 jimrgrant1
  • 02-12-2018

Answer:

y = [tex]\frac{4}{3}[/tex] x - 1

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - [tex]\frac{3}{4}[/tex] x - 3 is in this form

with slope m = - [tex]\frac{3}{4}[/tex]

the slope of a perpendicular line is the negative reciprocal of m, hence

[tex]m_{perpendicular}[/tex] = [tex]\frac{4}{3}[/tex]

(0 , - 1 ) is the y-intercept ⇒ c = - 1

y = [tex]\frac{4}{3}[/tex] x - 1  ← equation of perpendicular line


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