desheffern22 desheffern22
  • 03-10-2018
  • Mathematics
contestada

Write an equation of the line passing through point P(−8, 0) that is perpendicular to the line 3x−5y = 6.

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tramserran
tramserran tramserran
  • 03-10-2018

3x - 5y = 6

-3x         -3x

      -5y = -3x + 6

       [tex]\frac{-5y}{-5} = \frac{-3x}{-5} + \frac{6}{-5}[/tex]

          [tex]y = \frac{3}{5}x - \frac{6}{5}[/tex]  ⇒  m = [tex]\frac{3}{5}[/tex]

perpendicular slope (m⊥) = [tex]-\frac{5}{3}[/tex]

Point-Slope equation:

m = [tex]-\frac{5}{3}[/tex]    (x₁ , y₁)= (-8, 0)

y - y₁ = m(x - x₁)

y - 0 = [tex]-\frac{5}{3}[/tex](x - (-8))

    y = [tex]-\frac{5}{3}[/tex](x + 8)

    y = [tex]-\frac{5}{3}x - \frac{40}{3}[/tex]

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