Answer:- Solubility of KCl solution is 0.36 M.
Solution:- 2 kg of KCl dissolved into [tex]750cm^3[/tex] .
[tex]1cm^3[/tex] = 1 mL
So, [tex]750cm^3[/tex] = 750 mL
1000 mL = 1 L
So, 750 mL = 0.75 L
1 kg = 1000 g
So, 2 kg of KCl = 2000 g of KCl
Molar mass of KCl is 74.55 gram per mol.
So, moles of KCl = [tex]2000g(\frac{1mol}{74.55g})[/tex]
= 26.8 mol
Molar solubility of KCl = [tex]\frac{moles of KCl}{Liter of solution}[/tex]
molar solubility of KCl = [tex]\frac{26.8 mol}{0.75 L}[/tex]
molar solubility of KCl = 0.36 M
