sydneelittle3851 sydneelittle3851
  • 02-07-2018
  • Mathematics
contestada

Let the random variable x be equally likely to assume any of the values 1/12, 1/6, or 1/4. determine the mean and variance of x.

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 02-07-2018
The mean of x is
  (1/3)(1/12 + 1/6 + 1/4) = 1/6

The mean of the squares is
  (1/3)((1/12)² + (1/6)² + (1/4)²) = 7/216

The variance is the difference between the mean square and the square of the mean.
  7/216 -(1/6)² = 1/216

The mean of x is 1/6.
The variance of x is 1/216.
Answer Link

Otras preguntas

facts on Jason Scarpace
what is the difference between heterogeneous mixture vs homogenous mixture
can a single cell be a living thing? explain
Which of the following is considered a xanthine? a. Acetylcysteine b. Guaifenesin c. Theophylline d. Epinephrine HCL
Which of the following best describes one contribution of the Tuskegee Airmen during World War II? They flew missions over the US. They supported the troops. Th
The most important river in West Africa is the _____________. Senegal Gambia Niger Benue
what temperature is 10 degrees higher than minus 7 degrees
Which of the following could be a slant cross section of a right cone? a. sphere b. oval c. triangle d. circle
Which best describes what drew migrants to California in the 1930s? opportunities in coal mining family that had migrated previously the promise of free housing
Detached earlobes are dominant. A child inherits genes with the genotype: EE and ee. What is the chance that they will have detached earlobes? a. 25% chance b